<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[Topics tagged with backward difference]]></title><description><![CDATA[A list of topics that have been tagged with backward difference]]></description><link>https://community.secnto.com//tags/backward difference</link><generator>RSS for Node</generator><lastBuildDate>Mon, 08 Jun 2026 20:50:28 GMT</lastBuildDate><atom:link href="https://community.secnto.com//tags/backward difference.rss" rel="self" type="application/rss+xml"/><pubDate>Invalid Date</pubDate><ttl>60</ttl><item><title><![CDATA[Let P be any real number and h be the step size of any interval. Then the relation between h and P for the backward difference is given by]]></title><description><![CDATA[@zaasmi said in Let P be any real number and h be the step size of any interval. Then the relation between h and P for the backward difference is given by:

Let P be any real number and h be the step size of any interval. Then the relation between h and P for the backward difference is given by
Answer
x-x, = Ph
x- x, = P
x + x, = Ph
(x - x,)h= P

In the context of backward difference, the relationship between the step size  h  ￼ and the point  P￼ can be expressed as:
x - x_n = Ph
￼
Thus, the correct answer is x - x_n = Ph.
This expression indicates that the difference between a point ￼ and a previous point  x_n  ￼ can be represented as a multiple of the step size  h  ￼.
]]></description><link>https://community.secnto.com//topic/2668/let-p-be-any-real-number-and-h-be-the-step-size-of-any-interval-then-the-relation-between-h-and-p-for-the-backward-difference-is-given-by</link><guid isPermaLink="true">https://community.secnto.com//topic/2668/let-p-be-any-real-number-and-h-be-the-step-size-of-any-interval-then-the-relation-between-h-and-p-for-the-backward-difference-is-given-by</guid><dc:creator><![CDATA[zaasmi]]></dc:creator><pubDate>Invalid Date</pubDate></item></channel></rss>